Distributing Negative Exponents; Algebra.
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Distributing Negative Exponents; Algebra.

[From: ] [author: ] [Date: 12-10-17] [Hit: ]
For example:x^2x^(-3) = x^(2 + (-3)) = x^(-1) = 1/x, and x^2x^-2 = x(2 + (-2)) = x^0 = 1.If you practice these questions slowly, then everything will become automatic. Making test problems is an excellent way to learn new concepts, and you should definitely continue to do so.......
So I've created a little test problem to make sure that I correctly understand how to do it:

x^-2(x+2+x^2+x^-3+x^3)

The answer I got was:

1/x + 2/x^2 + 1 + 1/x^5 + x

Is that the correct way to distribute it? If not please show me the correct answer and add any additional information you think will be helpful.


P.S. What other basic concepts should I know about negative exponents? I'm new to them and want to make sure I understand them perfectly before moving on to different subjects.

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Hi, your answer is completely correct. I find the best way to deal with exponents in general is to remember the rule x^ax^b = x^(a + b). For example:
x^2x^(-3) = x^(2 + (-3)) = x^(-1) = 1/x, and x^2x^-2 = x(2 + (-2)) = x^0 = 1.

If you practice these questions slowly, then everything will become automatic. Making test problems is an excellent way to learn new concepts, and you should definitely continue to do so.
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