Maths question Algebra
Favorites|Homepage
Subscriptions | sitemap
HOME > > Maths question Algebra

Maths question Algebra

[From: ] [author: ] [Date: 12-09-28] [Hit: ]
..then n= 6,Hoping this helps!......
The middle term of the expansion of (ax+ay)^n is 14580x^3y^3 , Find the value of a and the value of n, where a,n are natural numbers.

Please explain how you got to that answer

-
If the middle term has x^3y^3, then n is 6, since the exponents add to 6

The coefficients on (x+y)^6 are C(6,0); C(6,1); etc

Then the fourth term has a coefficient of C(6,3)= (6!)/(3!*3!)= 20

(ax+ay)^6= (ax)^6+ 6(ax)^5(ay)^1+ ...

Then the fourth term is 20(ax)^3(ay)^3= 20a^3x^3 * a^3y^3= 20a^6* x^3y^3

Now 20a^6= 14580
a^6= 729
a= 729^(1/6)= 3

then n= 6, and a= 3

Hoping this helps!
1
keywords: Maths,Algebra,question,Maths question Algebra
New
Hot
© 2008-2010 http://www.science-mathematics.com . Program by zplan cms. Theme by wukong .