Need help to Solve logarithmic equation
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Need help to Solve logarithmic equation

[From: ] [author: ] [Date: 12-08-13] [Hit: ]
so you cant solve it,log 2 (x+2)-I assume thats an equals sign between the two logs. If so, seeing as you have logs with the same base on both sides you can just remove the logs.If thats a subtraction solve doesnt make any sense.-what you gonna do with this?......
http://imageshack.us/photo/my-images/716/photortg.jpg/

Sorry for the blurry picture.
Very confused about this problem, I'd appreciate it if you went through how to solve it step by step, thanks.

The instructions just say "solve".

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From what I can see, it is isn't an equation, so you can't solve it, but you can simplify it:

log 2 (x^2-4) - log 2 (x-2)

Use the log law: log a (b) -log a (c) = log a (b/c)

log 2 (x^2-4) - log 2 (x-2) = log 2 ((x^2-4)/(x-2))

Notice that x^2-4 can be factorised to: (x+2)(x-2):

It becomes:

log 2 (((x+2)(x-2))/(x-2))

Which simplifies to:

log 2 (x+2)

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I assume that's an equals sign between the two logs. If so, seeing as you have logs with the same base on both sides you can just remove the logs.
Then x^2 - 4 = x - 2
x^2 - x - 2 = 0
(x + 1)(x - 2) = 0
x = -1 or x = 2

If that's a subtraction "solve" doesn't make any sense.

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what you gonna do with this?
However in simple it means
Log(two) of (x+2)

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log _2 (x^2 - 4) / (x-2) = log_2 (x+2)
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