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Very confused about this problem, I'd appreciate it if you went through how to solve it step by step, thanks.
The instructions just say "solve".
Sorry for the blurry picture.
Very confused about this problem, I'd appreciate it if you went through how to solve it step by step, thanks.
The instructions just say "solve".
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From what I can see, it is isn't an equation, so you can't solve it, but you can simplify it:
log 2 (x^2-4) - log 2 (x-2)
Use the log law: log a (b) -log a (c) = log a (b/c)
log 2 (x^2-4) - log 2 (x-2) = log 2 ((x^2-4)/(x-2))
Notice that x^2-4 can be factorised to: (x+2)(x-2):
It becomes:
log 2 (((x+2)(x-2))/(x-2))
Which simplifies to:
log 2 (x+2)
log 2 (x^2-4) - log 2 (x-2)
Use the log law: log a (b) -log a (c) = log a (b/c)
log 2 (x^2-4) - log 2 (x-2) = log 2 ((x^2-4)/(x-2))
Notice that x^2-4 can be factorised to: (x+2)(x-2):
It becomes:
log 2 (((x+2)(x-2))/(x-2))
Which simplifies to:
log 2 (x+2)
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I assume that's an equals sign between the two logs. If so, seeing as you have logs with the same base on both sides you can just remove the logs.
Then x^2 - 4 = x - 2
x^2 - x - 2 = 0
(x + 1)(x - 2) = 0
x = -1 or x = 2
If that's a subtraction "solve" doesn't make any sense.
Then x^2 - 4 = x - 2
x^2 - x - 2 = 0
(x + 1)(x - 2) = 0
x = -1 or x = 2
If that's a subtraction "solve" doesn't make any sense.
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what you gonna do with this?
However in simple it means
Log(two) of (x+2)
However in simple it means
Log(two) of (x+2)
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log _2 (x^2 - 4) / (x-2) = log_2 (x+2)