Simplify as much as possible ((n+2)!) / (n!)
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Simplify as much as possible ((n+2)!) / (n!)

[From: ] [author: ] [Date: 12-08-13] [Hit: ]
(n + 2)(n + 1)n!/(n!(n + 2)(n + 1) = n^2 + 3n + 2-(n+2)!/n! = (n + 2)(n + 1) = n^2 + 3n + 2-(n+2)(n+1)(n!) / n!......
Help please

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((n + 2)!)/(n!) =
(n + 2)(n + 1)n!/(n!) =
(n + 2)(n + 1) = n^2 + 3n + 2

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(n+2)!/n! = (n + 2)(n + 1) = n^2 + 3n + 2

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(n+2)(n+1)(n!) / n!

(n+2)(n+1) = n^2 + 3n + 1
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