Factor k^2(3-k)+2k(k-3) **HELP**

Factor k^2(3-k)+2k(k-3)

Please go step by step and be thorough. I care more of how to do it rather than just being a slacker and getting the answer, please.
Thanks.

Factor out -1 from (3-k), because you want it to match (k-3).
This will get you:
-k^2(k - 3)+2k(k - 3)
Use the special kind of factoring. Format: c(a+b)+d(a+b) = (c+d)(a+b)
(-k^2 + 2k)(k - 3)
Then factor out -k from (-k^2 + 2k)
Final answer: -k(k - 2)(k-3).

k^2(3-k)+2k(k-3)
-k^2(k-3)+2k(k-3)
(k-3)(k^2-k)
k(k-3)(k-1)