Find the indicated sum:
http://webwork.math.ttu.edu/wwtmp/equati…
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http://webwork.math.ttu.edu/wwtmp/equati…
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we have 4(1/3)^n
starting with n=1 till n=13 we have a geometric series with a₁=1/3 and r=1/3
Sn = a₁(q^n -1) / q-1
S13 = (1/3)*((1/3)^13 -1) / 1/3 -1 ≈0.5
because originally we had 4(1/3)^n then: 4(0.5) = 2
starting with n=1 till n=13 we have a geometric series with a₁=1/3 and r=1/3
Sn = a₁(q^n -1) / q-1
S13 = (1/3)*((1/3)^13 -1) / 1/3 -1 ≈0.5
because originally we had 4(1/3)^n then: 4(0.5) = 2
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