How is Iz-1I = 2 the circle (x-1)^2 + y^2 = 4 (complex numbers)

[From: ] [author: ] [Date: 12-07-04] [Hit: ]

I'm having a lot of trouble understanding this, please explain, thanks.

z=x+iy
|z-1| = |x-1+iy| = √((x-1)²+y²) = 2

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