it's a non right triangle with
angle A 68 degrees
angle B 47 degrees
side B 15cm
angle C 65 degrees
and I have to find the length of side A. I tried using tan (15tan65) because I'm trying to find the opposite side of 15cm and the angle 65 is adjacent to side A I'm looking for, but in the textbook answers its not the correct answer. please help :( thanks
angle A 68 degrees
angle B 47 degrees
side B 15cm
angle C 65 degrees
and I have to find the length of side A. I tried using tan (15tan65) because I'm trying to find the opposite side of 15cm and the angle 65 is adjacent to side A I'm looking for, but in the textbook answers its not the correct answer. please help :( thanks
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Use the sine rule
a/sin(A) = b/sin(B) = c/sin(C)
Since b = 15cm and B (the angle) = 47 degrees
then a/sin(68) = 15/sin(47)
==> a = 15sin(68)/sin(47)
a/sin(A) = b/sin(B) = c/sin(C)
Since b = 15cm and B (the angle) = 47 degrees
then a/sin(68) = 15/sin(47)
==> a = 15sin(68)/sin(47)