a) y = 3^x + 3
b) y = 3^x+3
c) y = 2(1/2)^2x + 3
How would you find the X-intercept for these equations?
It says they're
(a) 4
(b) 27
(c) 5
In my textbook, but how they got that I am unsure.
b) y = 3^x+3
c) y = 2(1/2)^2x + 3
How would you find the X-intercept for these equations?
It says they're
(a) 4
(b) 27
(c) 5
In my textbook, but how they got that I am unsure.
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On the y-axis the value of x is 0.
So set x equal to 0 and solve.
For example, (a)
y = 3^x + 3
y = 3^0 + 3
y = 1 + 3
y = 4
So set x equal to 0 and solve.
For example, (a)
y = 3^x + 3
y = 3^0 + 3
y = 1 + 3
y = 4
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To get the Y-Intercept in y=mx+b, b is always the y=intercept.
So, in a) 3 is the y-intercept
b) 3
c) 3
To find the x-intercept, you must plug in a 0 for x and y.so for a) (0)=3^(0)=3 do the math and i believe the x-intercept is (0,3)
b) (0,3)
C) (0,3)
So, in a) 3 is the y-intercept
b) 3
c) 3
To find the x-intercept, you must plug in a 0 for x and y.so for a) (0)=3^(0)=3 do the math and i believe the x-intercept is (0,3)
b) (0,3)
C) (0,3)
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I think you mean the Y-intercept. This occurs when x=0. So just set x=0 and solve for y.
the first...
y=3^0+3 = 1+3 = 4
Im sure you can do the rest.
the first...
y=3^0+3 = 1+3 = 4
Im sure you can do the rest.