A displacer has a diameter of 4 in. and a length of 30 inches.If it is submerged to a depth of of 20 in. in a

liquid with a specific gravity of 0.8, how many pounds of upward buoyancy force will be exerted on the displacer?

B = (d liq.)(V)(g/gc) -----> for British/English units

*where:
B = bouyant force
d liq. = density of liquid
V = volume of material submerged in liquid
g/gc = 1 lbf/lbm

V = Area(base) x height(depth)

diameter = 4 in. = 0.3333 ft.
height (depth) = 20 in. = 1.667 ft.

V = (3.1416)[(0.3333 ft.)^2 / 4] (1.667 ft.)
V = 0.1454 ft^3

d (liq.) = (62.4 lbm/ft^3)(0.8) = 49.92 lbm/ft^3

B = (49.92 lbm/ft^3)(0.1454 ft^3)(1 lbf/lbm)

B = 7.26 lbf ------> FINAL ANSWER
(Note: "lbf" = pound force)