Please help me in chemistry! Find the percent yield
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Please help me in chemistry! Find the percent yield

[From: ] [author: ] [Date: 12-05-17] [Hit: ]
473 g P) / (30.97376 g P/mol) = 0.(3.25 g Cl2) / (70.9064 g Cl2/mol) = 0.0.......
Please help

2P+5CI2=>2PCI5

.473g P and 3.25 CIs
Actual yield=2.12g PCI5
Find the percent yield. Please show work.

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2 P + 5 Cl2 → 2 PCl5

(0.473 g P) / (30.97376 g P/mol) = 0.015271 mol P

Supposing the missing units to be grams:
(3.25 g Cl2) / (70.9064 g Cl2/mol) = 0.045835 mol Cl2

0.015271 mole of P would react completely with 0.015271 x (5/2) = 0.0381775 mole Cl2, but there is more Cl2 present than that, so Cl2 is in excess and P is the limiting reactant.

(0.015271 mol P) x (2/2) x (208.2398 g PCl5/mol) = 3.18 g PCl5 in theory

(2.12 g) / (3.18 g) = 0.667 = 66.7%
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