Algebra question, help please

Consider the two sets of consecutive numbers:

S1: {415, 417, ... 511}
S2: {1, 15, 29, ... 629}

Which of the following is true?

A: S1 has 2 more numbers than S2.
B: S1 has 1 more than S2.
C: S1 and S2 have the same count of numbers.
D: S2 has more numbers than S1.
E: S1 has 3 more numbers than S2.

Equations:

415 + (n-1)2
or 413 + 2n

1 + (n-1)14
or 14n - 13

Find out the number of terms for each:
413 + 2n = 511 so n = 49
14n - 13 = 629 so n = 46


So E is the answer

D: S2 has more numbers that S1.
I would say this is the best choice because the last number in S2 is 629 meaning that it contains a range up to 629, while S1 only goes to 511. So, therefore S2 has more numbers than S1