How do I solve these probabilities problems
Favorites|Homepage
Subscriptions | sitemap
HOME > > How do I solve these probabilities problems

How do I solve these probabilities problems

[From: ] [author: ] [Date: 12-05-17] [Hit: ]
3. a one-digit number followed by a number divisible by 3 in consecutive draws without replacement.-1.Out of the 50 numbers, 4 numbers have two digits that are the same, and 9 numbers are single-digit numbers.......
How do I solve these probabilities problems?

An experiment consists of placing the numbers 1-50 in a hat. If 2 numbers are drawn, find the probability of drawing:

1. a number with 2 digits that are the same followed by a single-digit number with replacement.

2. a number divisible by 10 followed by a number divisible by 5 without replacement.

3. a one-digit number followed by a number divisible by 3 in consecutive draws without replacement.

-
1. Out of the 50 numbers, 4 numbers have two digits that are the same, and 9 numbers are single-digit numbers.

P(# with two digits the same, then single digit #, w/ replacement)
= (4/50)(9/50)
= 9/625.

2. Out of the 50 numbers, 5 numbers are divisible by 10, 10 numbers are divisible by 5, and all numbers divisible by 10 are divisible by 5. So selecting a number divisible by 10 on the first draw reduces, by one, the number of remaining numbers divisible by 5 for the second draw.

P(# divisible by 10, followed by # divisible by 5, w/o replacement)
= (5/50)(9/49)
= 9/490.

3. Out of the 50 numbers, 9 numbers are one-digit, 16 numbers are divisible by 3, 3 of the one-digit numbers are divisible by 3, and 6 of the one-digit numbers are not divisible by 3.
Selecting one of the 3 one-digit numbers divisible by 3 on the first draw reduces, by one, the number of remaining numbers divisible by 3 for the second draw.
Selecting one of the 6 one-digit numbers not divisible by 3 on the first draw does not affect the number of remaining numbers divisible by 3 for the second draw.

P(one-digit #, followed by # divisible by 3, w/o replacement)
= (3/50)(15/49) + (6/50)(16/49)
= 9/490 + 48/1225
= 141/2450.

Lord bless you today!
1
keywords: solve,How,these,do,probabilities,problems,How do I solve these probabilities problems
New
Hot
© 2008-2010 http://www.science-mathematics.com . Program by zplan cms. Theme by wukong .