How do you answer this algebra question explain

B) (10x/3+x) / (4/5(3+x)=
C) (2/3)+((m-2n)/(m+3n)=
D) (y^2-1)/ (3y+3)=

Hello

B.
dividing by a fraction means multiplying by the reverse fraction

10x / (3+x) * 5(3+x) / 4

= 10x * 5 * (3+x) / 4 * (3+x) = 50x * (3+x) / 4 * (3+x)

You can divide over and under by 2 and by (3+x) ==> 25x / 2 ==> Answer

C.

That is addition of fractions.
The first one has 3 as denominator
The second one has (m+3n)
The common denominator will be 3(m+3n)

2(m+3n) / 3(m+3n) + 3(m-2n) / 3(m+3n) = [2(m+3n) + 3(m-2n)] / 3(m+3n)

[2m + 6n + 3m - 6n] / 3(m+3n) = 5m / 3(m+3n) ==> Answer

D.
This supposes that you know the formula that says : a² - b² = (a + b)(a - b)
It is very important. I mean you must know it !

(y² - 1) is such, since y² is a square, 1 is a square, and you have the sign "-"

(y² - 1) = (y + 1)(y - 1)

and (3y + 3) = 3(y + 1)

So you have (y + 1)(y - 1) / 3(y + 1) you can simplify by (y + 1)

and you have (y - 1) / 3 ==> Answer

Hope it helped

Bye !

B) (10x/3+x) / (4/5(3+x)=
→{(10x)/(3+x)} × {5(3+x)/4}=
=(10x) × (5/4) = 25x/2

(10x/3+x) / (4/5(3+x)=

10x / (3+x) * 5(3+x) / 4 = 50x(3+x) / 4(3+x)

50x / 4

50/4 x

12.5(x)