Calculus help. Solve for x

I'm not sure on how to do this.

e^(e^x) = 3

First, we multiply both sides by ln(x) or the natural log of x. This gives us:
ln(e^(e^x)) = ln 3
Because ln(x) and e^x are inverse functions of each other we get the equality:
ln(e^x) = x
Applying this to our previous problem, we can simplify to:
e^x = ln 3
If we do the same thing again, we get:
ln(e^x) = ln(ln(3))
x = ln(ln(3))
Which is approximately:
x = 0.094