Factor completely. Please!

4b^2 + 13b +3

4b²+13b+3
4b²+(12b+b)+3
(4b²+12b)+(b+3)
4b(b+3)+(b+3)
(4b+1)(b+3)

Solution: (4b+1)(b+3)

Always remember that
(ax + b)(cx + d)
= acx^2 + (ad +bc)x + bd
Here: bd = 3 = 3 + 1
(ad + bc) = 13 = 4 * 3 + 1
ac = 4 = 4 * 1
so
4b^2 + 13b +3
= (4b + 1)(b + 3).

4b^2 + 13b + 3 =
(4b + 1)(b + 3)

(4b + 1)(b + 3)

You're a slave driver


(b + 3)(4b + 1) = 0