A fishing boat leaves port with a compass bearing* of 80 degrees at 8 miles per hour for 5 hours, then turns to a bearing of 25 degrees at 12 miles per hour for 3 hours, and finally changes to a bearing of 330 degrees at 17 miles per hour for 2 hours. From this point, the boat heads directly back to port at 18 miles per hour.
Find the time it takes the boat to return to port: ______hours
Find the boat's bearing as it returns to port: ________degrees
*measured in degrees clockwise from N
If you know how to do this, please help me! If you get decimals, if you could use them all so we I have an exact answer, that would be awesome. Thank you!
Find the time it takes the boat to return to port: ______hours
Find the boat's bearing as it returns to port: ________degrees
*measured in degrees clockwise from N
If you know how to do this, please help me! If you get decimals, if you could use them all so we I have an exact answer, that would be awesome. Thank you!
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assuming the port is far away from north or south pole
change the polar data in a Cartesian data first
x = R * cos a
y = R * sin a
for example first trip
X1 = 8*5 * cos 80
Y1 = 8*5 * sin 80
and
X2 = 12*3 * cos25
Y2 = 12*3 * sin25
after finding them , add them
X = X1 + X2 + X3 + ...
Y = y1 + y2 + y3 + ...
now change Cartesian data to polar data again
R = root( x² + y² )
and
alpha = arc tan ( Y/X)
time = R/18
change the polar data in a Cartesian data first
x = R * cos a
y = R * sin a
for example first trip
X1 = 8*5 * cos 80
Y1 = 8*5 * sin 80
and
X2 = 12*3 * cos25
Y2 = 12*3 * sin25
after finding them , add them
X = X1 + X2 + X3 + ...
Y = y1 + y2 + y3 + ...
now change Cartesian data to polar data again
R = root( x² + y² )
and
alpha = arc tan ( Y/X)
time = R/18