Solve y=2x^2+bx+c a porabola with points (-2,10) and (4,10).
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Solve y=2x^2+bx+c a porabola with points (-2,10) and (4,10).

[From: ] [author: ] [Date: 12-04-13] [Hit: ]
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Find b and c.

plz show work

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10=2(-2)^2+b(-2)+c
10=2(4)^2+4b+c

10=8-2b+c
10=32+4b+c


4=-4b+2c
-22=4b+c
-18=3c
c=-6
b=-4

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y = -6 - 4 x + 2 x^2
1
keywords: porabola,and,10,bx,points,Solve,with,Solve y=2x^2+bx+c a porabola with points (-2,10) and (4,10).
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