ok so I have this problem I'm not really sure about. I have to factor this
original = 4x^2 + 15x + 6
-15 ± √15^2 - 4 (4) (6)
_______________________
-15 ± √225 - 95
_______________________
-15 ± √129
________
2(4)
________________________
-15 ± √129
________
8
Now I'm not sure how to continue. I need it so I get
X = ?
I know its 2 numbers but I forgot how to do it.
original = 4x^2 + 15x + 6
-15 ± √15^2 - 4 (4) (6)
_______________________
-15 ± √225 - 95
_______________________
-15 ± √129
________
2(4)
________________________
-15 ± √129
________
8
Now I'm not sure how to continue. I need it so I get
X = ?
I know its 2 numbers but I forgot how to do it.
-
You solve that equation twice: once for the addition and once for the subtraction:
x1 = (-15 + √129)/8 = -0.455...
x2 = (-15 - √129)/8 = -3.29...
x1 = (-15 + √129)/8 = -0.455...
x2 = (-15 - √129)/8 = -3.29...
-
the formula says x= (-b(+/-)√b^2-4ac)/2a
so x =
-15 ± √129
________
8
and it means x=
-15 + √129
________
8
or
=-15 - √129
_______
8
no more simplification needed
so x =
-15 ± √129
________
8
and it means x=
-15 + √129
________
8
or
=-15 - √129
_______
8
no more simplification needed