Factor completely 7x^5-21x^4+35x^3
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Factor completely 7x^5-21x^4+35x^3

[From: ] [author: ] [Date: 12-03-10] [Hit: ]
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7x^5-21x^4+35x^3
=7(x^5-3x^4+5x^3)
=7x^3(x^2-3x+5)

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7x^5-21x^4+35x^3 = 7x^3(x^2-3x+5)

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7x^3(x^2-3x+5)
1
keywords: completely,35,Factor,21,Factor completely 7x^5-21x^4+35x^3
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