How would i factor x^8 - 1

explain all steps

Difference of two squares

(x^4 + 1)(x^4 - 1)
(x^4 + 1)(x^2 + 1)(x^2 - 1)
(x^4 + 1)(x^2 + 1)(x + 1)(x - 1)

x^8 - 1 = (x^4+1)(x^2+1)(x+1)(x-1)