Not exactly sure what you are asking:
1) solubility of NaNO3 in 100g water at 20°C is 88.3g - so 20g is unsaturated
2) molar mass NaNO3 = 85g/mol
20g = 20/85 = 0.235 mol NaNO3 used.
Is that what you want.
1) solubility of NaNO3 in 100g water at 20°C is 88.3g - so 20g is unsaturated
2) molar mass NaNO3 = 85g/mol
20g = 20/85 = 0.235 mol NaNO3 used.
Is that what you want.