Help with a Stats problem
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Help with a Stats problem

[From: ] [author: ] [Date: 12-03-10] [Hit: ]
(ii) the miss can be any of the 3 shots,no, no, i told you three out of 3 was ok! look, every time a shot is fired,......
A hockey player makes 30% of his shots. He takes 3 shots. what is the probability that he makes 3 out of 3 shots?

2 out of 3 shots?

Im not sure how to solve this. do we do (3/10) x (3/10) x (3/10) for 3 shots.
and (3/10) x (3/10) for two shots?

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three out of 3 is ok, but for 2 out of 3, you have to consider that
(i) one is a miss, that has to be accounted for
(ii) the miss can be any of the 3 shots, so
Pr = 3 * 3/10 *3/10 *7/10
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your AD
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no, no, i told you three out of 3 was ok! look, every time a shot is fired, you either hit (H) or miss (M) if it is 3 hits (HHH) or 3 misses (MMM) it can occur in only 1 way, but two hits an a miss, eg can occur as HHM, HMH or MHH, so we multiply by 3
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