How many ways can 5 boys and 3 girls be arranged in a line such that no two girls are adjacent to each other

x's mark permissible spots for girls in the string below

x B x B x B x B x B x

the girls can be placed in 6P3 = 6*5*4 = 120 ways
and the boys can be permuted in their places in 5! ways
ans: 120*5! = 14,400 <------
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2 ways. starting the line with a boy
or starting the line with 2 boys.

Look up permutation formula online then solve