Two angles that are complimentary if their sum is 90 degrees. Find the measures of two complimentary angles if one angle is twice the other.
I need an equation, I tried everything and it doesn't work :(
I need an equation, I tried everything and it doesn't work :(
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(2x) + x = 90
3x = 90
x = 30
Angles are 30° and 60°
PS
Complementary not complimentary.
3x = 90
x = 30
Angles are 30° and 60°
PS
Complementary not complimentary.
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Thank you---good luck.
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Let one angle be x
The other angle must be 90 - x (since their sum is 90 degrees being complementary)
Let x = 2(90 - x)
Solve for x
x = 180 - 2x
3x = 180
x = 60
The two angles are 60 and 90-60 = 30 degrees
The other angle must be 90 - x (since their sum is 90 degrees being complementary)
Let x = 2(90 - x)
Solve for x
x = 180 - 2x
3x = 180
x = 60
The two angles are 60 and 90-60 = 30 degrees
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Let one angle be x.
Then the other angle is 2x.[twice the other]
2x + x = 90 [sum of the angles must be 90 as they are complementary]
3x = 90
x = 30 degree.
2x = 2(30)
= 60 degree
HOpe this helped
Then the other angle is 2x.[twice the other]
2x + x = 90 [sum of the angles must be 90 as they are complementary]
3x = 90
x = 30 degree.
2x = 2(30)
= 60 degree
HOpe this helped
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if one angel is x
then other angle is 2x
their sum equals to 90
x+2x = 90
3x = 90
x = 30
then one angle is 30 degrees and other is 60 degrees
then other angle is 2x
their sum equals to 90
x+2x = 90
3x = 90
x = 30
then one angle is 30 degrees and other is 60 degrees