Please help solve this short/easy math problem for 10 points

8y²-9y+1=0

AND if you can, also this one: 4x^3-12x^2+8x=0

show work. thanks!

8y² - 9y + 1 = 0
(8y - 1)(y - 1) = 0 {factored into two binomials}
8y - 1 = 0 or y - 1 = 0 {set each factor equal to 0}
8y = 1 or y = 1 {added 1 in both equations}
y = 1/8 or y = 1 {solved each equation for y}

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4x³ - 12x² + 8x = 0
4x(x² - 3x + 2) = 0 {factored 4x out}
4x(x - 2)(x - 1) = 0 {factored into two binomials}
4x = 0 or x - 2 = 0 or x - 1 = 0 {set each factor equal to 0}
x = 0 or x = 2 or x = 1 {solved each equation for x}

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8y^2-9y+1=0,
(8y-1)(y-1)=0,
y=1/8, 1.
Answer: y=1/8, 1.

4x^3-12x^2+8x=0,
4x(x^2-3x+2)=0,
4x(x-2)(x-1)=0,
x=0, 2, 1.
Answer: x=0, 2, 1.

(8y-1)(y-1) set to zero.
(8y-1)=zero.
Add one to both sides.
8y=1
divide 8 on both sides
Y=8
then do the same for (y-1) which equals 1.

for the first one use the quadratic equation y= 1/8 and 1
second
factor out 4x
4x(x^2 -3x + 2)=0
4x(x-1)(x-2)=0
x=1,2, 0

1. (8y-1) (y-1) = 0
8y-1= 0 y-1=0
y=-1/8 y=1
y=-1/8, 1

2. 4x(x^2 - 3x + 2) =0
4( x-1) (x-2) =0
x= 1, 2