okay guys sorry for being a pest but i wonder so here it goes and to the best answer i will give the biggest reward i can give.
okay so i think that this solution to this system is (4,-6).But my older bro thinks it's (8,2).so who is correct.
2x-3y=10
6y=4x-20
but i really don't get it much and my bro does not want to help me he only told me it's one of those 2 answers.
okay so i think that this solution to this system is (4,-6).But my older bro thinks it's (8,2).so who is correct.
2x-3y=10
6y=4x-20
but i really don't get it much and my bro does not want to help me he only told me it's one of those 2 answers.
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2x - 3y = 10 equation 1
6y = 4x - 20 equation 2
Divide equation 2 by 2 to get:
3y = 2x - 10
Re-ordering, we get:
2x - 3y = 10
which is the same as equation 1
Given these two equations, the value of x and y cannot be determined
6y = 4x - 20 equation 2
Divide equation 2 by 2 to get:
3y = 2x - 10
Re-ordering, we get:
2x - 3y = 10
which is the same as equation 1
Given these two equations, the value of x and y cannot be determined
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2x-3y=10
6y=4x-20
2x-3y=10
-4x+6y=-20
Multiply the first equation by 2
4x-6y=20
-4x+6y=-20
These equations are the same so any solution that works in one is a solution of the other.
Check (4,-6) and (8,2) to see if they work. Substitute and check:
2(4) - 3(-6) =10
8 + 18 = 26 not 10 so (4,-6) is incorrect.
2(8) -3(2) = 16 - 6 = 10
6(2) = 4(8) -20
12 = 32 - 20 = 12 so (8,2) is a correct solution.
But so is (5,0) or (11,4). There are many correct solutions.
6y=4x-20
2x-3y=10
-4x+6y=-20
Multiply the first equation by 2
4x-6y=20
-4x+6y=-20
These equations are the same so any solution that works in one is a solution of the other.
Check (4,-6) and (8,2) to see if they work. Substitute and check:
2(4) - 3(-6) =10
8 + 18 = 26 not 10 so (4,-6) is incorrect.
2(8) -3(2) = 16 - 6 = 10
6(2) = 4(8) -20
12 = 32 - 20 = 12 so (8,2) is a correct solution.
But so is (5,0) or (11,4). There are many correct solutions.
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The two expressions are the same. The second expression is just -2 times the first expression. So there is no solution since the two systems are just the same. If you arrange the first expression after the second expression you get:
-3y = -2x + 10.
If you multiply across by -2 you'll have:
6y = 4x - 20
which is equation 2.
So you can only solve x in terms of y or y in terms of x. No real solution.
-3y = -2x + 10.
If you multiply across by -2 you'll have:
6y = 4x - 20
which is equation 2.
So you can only solve x in terms of y or y in terms of x. No real solution.
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6y = 4x - 20
-4x + 6y = -20
-4x + 6y = -20
2x - 3y = 10
-4x + 6y = -20
4x - 6y = 20
0 = 0
infinite solutions
you are both wrong
they are the same equation (line)
2x - 3y = 10
-3y = -2x + 10
y = (2/3)x - 10/3
6y = 4x - 20
y = (4/6)x - 20/6
y = (2/3)x - 10/3
-4x + 6y = -20
-4x + 6y = -20
2x - 3y = 10
-4x + 6y = -20
4x - 6y = 20
0 = 0
infinite solutions
you are both wrong
they are the same equation (line)
2x - 3y = 10
-3y = -2x + 10
y = (2/3)x - 10/3
6y = 4x - 20
y = (4/6)x - 20/6
y = (2/3)x - 10/3
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infinate soultion... the equations equal eachother
4x-20=4x-20
6y+20=6y+20
4x-20=4x-20
6y+20=6y+20
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(8,2). 8 is the "x" value so it has to stay consistent even if the variable placement switches.
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It is (8,2) because 2(8)-3(2)=10 2x8=16 3x2=6 16-6=10
Also 6(2)=4(8)-20 6x2=12 4x8=32 so 12=32-20 and 32-20=12
Also 6(2)=4(8)-20 6x2=12 4x8=32 so 12=32-20 and 32-20=12
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Tip : what you do to one side of the equation you must do to the other.
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8,2 is correct