Let u = 1.5piX+.25pi
du = 1.5pi dx
dx = (1/1.5pi) = 2/3pi
∫ sin(1.5piX+.25pi) dx = (2/3pi) ∫ sin(u) du = (-2/3pi) cos(u) + C
=(-2/3pi) cos(1.5piX+.25pi) +C
du = 1.5pi dx
dx = (1/1.5pi) = 2/3pi
∫ sin(1.5piX+.25pi) dx = (2/3pi) ∫ sin(u) du = (-2/3pi) cos(u) + C
=(-2/3pi) cos(1.5piX+.25pi) +C
-
http://answers.yahoo.com/question/index;_ylt=Au3VJxTY5FGcwuPSVZDxEWHty6IX;_ylv=3?qid=20120220090757AA7dwM9
-
dy/dx = sin(1.5pix+0.25pi) y = - cos (1.5pix +0.25pi)/1.5pi +c
-
No.