How to do this equation with order of operations

(2-7) x (3 - 6/3)^2 ÷ 3 + 2/5
I got 63/27

order of operations can be remembered as BEDMAS (Brackets before Exponents before Division and/or Multiplication before Addition and/or Subtraction

Brackets
(-5) x (1)^2 ÷ 3 + 2/5

Exponents
-5 x 1 ÷ 3 + 2/5

Division and/or Multiplication
-5/3 + 2/5

Addition and/or Subtraction
-19/15 or -1 4/15

Note: Fraction are technically Division if you're working in decimals

(2-7) x (3 - 6/3)^2 ÷ 3 + 2/5

the 6/3 simplifies to 2
(2-7) x (3 - 2)^2 ÷ 3 + 2/5

parenthesis
(-5) x (-1)^2 ÷ 3 + 2/5

exponents
(-5) x 1 ÷ 3 + 2/5

multiplication
-5 ÷ 3 + 2/5

division
-5/3 + 2/5

addition
-4/15

your answer is -4/15

Parenthesis

-5 x 1^2 / 3 + 2/5

Exponent

-5 x 1 / 3 + 2/5

Division/Multiplication

-5/3 + 2/5

Last add and subtract (you'll need a common denominator if you leave it in fractions)

-25/15 + 6/15

-19/15

you do pemdas. which means parenthesis first, then exponents...and so on.

p: parenthesis

e: exponents

m: multiplication

d: division

a: addition

s: subtraction

(2-7) x (3 - 6/3)^2 ÷ 3 + 2/5
(-5) x (3 - 2)^2 ÷ 3 + 2/5
(-5) x (1)^2 ÷ 3 + 2/5
(-5) x (1) ÷ 3 + 2/5
-5 x ÷ 3 + 2/5
-5/3 ÷ 2/5
-25/6

(2-7) x (3 - 6/3)^2 ÷ 3 + 2/5
-5 x 1^2 ÷ 3 + 2/5
-5 x 1 ÷ 3 + 2/5
-5 ÷ 3 + 2/5
-1.6 + 2/5
-1.6 + 0.4
-1.2

(2-7) x (3 - 6/3)^2 ÷ 3 + 2/5
(-5) x (1)^2 ÷ 3 + 0.4
-5/3 + 0.4
-1.6'+0.4
-1.26'