Please respond this quickly!!!!!

Given cos(2α)=−47/81 and π/2<2α<π, find exact values of the six trigonometric functions.
Note: You are not allowed to use decimals in your answer.
sin(α) = ................

cos(α) = ........................

tan(α) = ......................

csc(α) = .

sec(α) = .....................

cot(α) = ........................

cos(2a)=-47/81
cosa^2-sina^2=-47/81
1-2sina^2=-47/81
-2sina^2=-128/81
sina^2=64/81
sina=8/9 = 0.89

now sina^2+cosa^2=1
therefore 64/81 + cosa^2=1
cosa^2=17/81
cosa=sqrt17/9

tana=8/9*9/sqrt17 = 8sqrt17
csca=1/sina = 1/8/9 = 9/8
seca=1/cosa=1/sqrt17/9 = 9/sqrt17
cota=1/tana=1/8sqrt17