How do I calculate the percent of cases falling between the two z-scores: z= -.38 and z= 1.63???
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fatamorgana1989 -
If you have a Standard Normal table, perform the following procedure:
Find the area under the Standard Normal curve that is less than 1.63, then subtract the area that is less than -0.38:
Answer = P(z < 1.63) - P(z < -0.38)
= 0.9484 - 0.3520 = 0.5964
= 59.64%
Hope that helped
If you have a Standard Normal table, perform the following procedure:
Find the area under the Standard Normal curve that is less than 1.63, then subtract the area that is less than -0.38:
Answer = P(z < 1.63) - P(z < -0.38)
= 0.9484 - 0.3520 = 0.5964
= 59.64%
Hope that helped