Math question.........

The volume of a pyramid is 224.4cm^3. The area of its base is 34cm^2.
What is its height to one decimal place?

Is it a square pyramid or a triangular-base pyramid?

Assuming it's a square-base pyramid, the formula for finding the volume would be V = 1/3(a)(h), where V is volume, A is area, and H is height. So when we're given the area of the base and the volume, we need to alter this formula a bit.
So our new formula will be H = (V/a)3
(The reason we multiply by three in this new formula is because 3 is the reciprocal of 1/3).

H = (224.4 / 34)3
H = (6.6)3
H = 19.8

The volume of a pyramid is 224.4cm^3. The area of its base is 34cm^2.
What is its height to one decimal place?

Volume of a pyramid = (1/3) B h

where B is the area of the base, h is the height

224.4 = (1/3)(34)(h)

solve for h: give it a go...you can do it...you can try !

¶

[h = 19.8 cm]

The volume of any solid that has some base, and extends to a single point is 1/3 Ah
where A is the area of the base and h is the hight perpendicular to the base through the vertex.

V * 3 / A = h

So 224.4 * 3 / 34 = 19.8

The volume of a pyramid is 224.4cm^3. The area of its base is 34cm^2.
What is its height to one decimal place?
Height of pyramid is given by 3Volume / Area of base = 2*224.4 cm^3 / 34 cm^2 = 19.8 cm ANSWER