Help with math homework? Im so confused.

The average milage on a car is 32 mi/gal. The actual milage may vary by at most 3 mi/gal. What are the minimum and maximum distances the car can travel on a full tank of gas if the tanks capacity is 11 gal?
A. 29 mi, 35 mi
B. 32 mi, 35 mi
C. 319 mi, 385 mi
D. 349 mi, 355 mi

Min: 32-3=29 times 11=319
Max 32+3=35 times 11=385

answer is C

What this question is telling you -

You have a car with a tank that holds 11 gallon milk bottles of gas.
The car can drive 32 miles on one gallon of gas, give or take three miles.

This give or take three miles per gallon means the car can go 29 miles or 35 miles per gallon.

To figure out how far the car will take you on 11 gallons of gas, you multiply 29 and 11 for the lesser distance and 35 times 11 for the farther distance.

Therefore, 11 * 29 = 319 miles
and 11 * 35 = 385 miles

the answer is C here's why... the mileage may vary 3mi/gal either way. so assume its low all the time so you'd subtract 3mpg from the 32 giving 29 then multiply it by the 11gal it has. next do the opposite but assume it's a best case scenario so assume 35mpg the multiply that by 11 again.

Engineering student

The average mileage on a car is 32 mi/gal.
The actual mileage may vary by at most 3 mi/gal.
What are the minimum and maximum distances the car can travel on
a full tank of gas if the tanks capacity is 11 gal?
Answer:
C. 319 mi, 385 mi

C. If you have 11 gallons of gas, and you can get a minimum of 29 mpg (32-3=29) and a maximum of 35 mpg (32+3=35), then you can get anywhere from 29*11= 319 and a maximum of 35*11=385.

= between 11/(1/32) - 3(11) and 11/(1/32) + 3(11)
= between 352 - 33 and 352 + 33
= between 319 and 385

Answer: C. Between 319 miles And 385 miles

milage = 32(+-) 3

max= 35 mi/gal--------------->35*11=385 mi

min = 29 mi/gal----------------> 29*11=319 mi

D. because all your doing is multiplying 32 by 11