Algebra 2 help, please!

"Find all real zeros of X for which the functions are equal. Give your answers to the nearest hundredth"
p(x)=x^2; q(x) = x^3 - 2x^2 - 12x + 10

and write a polynomial function, P, in factored form by using the given information.
P is of degree; zeroes: 2, 3i, -3i; p(0)= 36

I honestly have no idea what to do! I just need a walk through the problems, because I am soo lost! If I know how to do these two, then I can do every other problem, please help! Thanks!(:

p(x)=q(x) you get


x^3-3x^2-12x+10=0

±1,±2,±5,±10 try to find one of them its image under p(x) is zero.You have x=5

Then x-5 is a factor of the new polynomial.Divide the polynomial by x-5

5 | 1 -3 -12 10
........5 10 -10
-------------------------
.......1 2 -2 0

then the polynomial is equal to

(x-5((x^2+2x-2)

Use the quadratic formula to find the zeros of x^2+2x-2

x=[-2±sqrt(10)]/2 evaluate this you get x=-2.73 and x=0.73
The zeros are{-2.73,0.73,5}

You have the polynomial in the form

a(x-2)(x-3i)(x+3i) where a is the leading coefficient.Use FOIL to expand you get

a(x^3-2x^2+9x-18)

P(0)=a(0-0+0-18)=36

-18a=36

a=-2

then you get

p(x)=-2x^3+4x^2-18x+36