... tan ( 7π/12 )
= tan [ (3π/12) + (4π/12) ]
= tan ( π/4 + π/3 )
= ( tan π/4 + tan π/3 ) / ( 1 - tan π/4 tan π/3 )
= ( 1 + √3 ) / ( 1 - √3 ) ........................................… Ans.
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= tan [ (3π/12) + (4π/12) ]
= tan ( π/4 + π/3 )
= ( tan π/4 + tan π/3 ) / ( 1 - tan π/4 tan π/3 )
= ( 1 + √3 ) / ( 1 - √3 ) ........................................… Ans.
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You are Welcome, MG !
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