How to estimate infinite sums
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How to estimate infinite sums

[From: ] [author: ] [Date: 11-12-12] [Hit: ]
For instance, if we need the error less than 1/1000,==> k > 7/2.So, we need at least 4 terms for the desired accuracy.I hope this helps!......
How would you do this problem?

sum from k = 1 to infinity, [(-1)^k] / (2k+1)^3

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This is an alternating series; so the error after n terms is bounded above by the absolute value of the following (n+1)-th term.

For instance, if we need the error less than 1/1000, we require that
1/(2(k+1) + 1)^3 < 1/1000
==> (2k+3)^3 > 1000
==> 2k + 3 > 10
==> k > 7/2.

So, we need at least 4 terms for the desired accuracy.

I hope this helps!
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