Simple enough
C*(a) = D*(1 0)
(b) (0 (-1))
Best way I have to write it out.
I need to find further coefficients on a and b so I need to multiply the matrices through how?
Thanks for the help!
C*(a) = D*(1 0)
(b) (0 (-1))
Best way I have to write it out.
I need to find further coefficients on a and b so I need to multiply the matrices through how?
Thanks for the help!
-
There can be no solution.
The product on the left requires that C be a scalar or that C be an m x 2 matrix. This means that the left side is 2 x 1 or m x 1.
The product on the right requires that D be a scalar or that D be an n x 2 matrix. So the expression on the right is 2 x 2 or n x 2.
For all pairs of numbers m and n the dimensions on each side do not match.
The product on the left requires that C be a scalar or that C be an m x 2 matrix. This means that the left side is 2 x 1 or m x 1.
The product on the right requires that D be a scalar or that D be an n x 2 matrix. So the expression on the right is 2 x 2 or n x 2.
For all pairs of numbers m and n the dimensions on each side do not match.
-
I'm assuming C and D are matrices....
C * (#1) = D*(#2) can never be true.
Suppose C has dimensions of n*2 since #1 has 2 rows, C must have 2 columns.
And C* #1 will have a dimension of n*1
Suppose D has dimensions of m*2 since #2 has 2 rows, D must have 2 columns.
D * #2 will have a dimension of m*2.
Matrices with different dimensions can't be equal....
Perhaps you are talking about inverse matrices?
C * (#1) = D*(#2) can never be true.
Suppose C has dimensions of n*2 since #1 has 2 rows, C must have 2 columns.
And C* #1 will have a dimension of n*1
Suppose D has dimensions of m*2 since #2 has 2 rows, D must have 2 columns.
D * #2 will have a dimension of m*2.
Matrices with different dimensions can't be equal....
Perhaps you are talking about inverse matrices?