What are the x– and y–intercepts of the graph of y = 2x2 + 4x – 6

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What are the x– and y–intercepts of the graph of y = 2x^2 + 4x – 6?

y = 2x² + 4x - 6

x-int.: y = 0:

2x² + 4x - 6 = 0
x² + 2x - 3 = 0
(x + 3)(x - 1) = 0

If the product of two terms equals zero, then one or both terms equal zero.

If x + 3 = 0,
x = - 3

If x - 1 = 0,
x = 1

x-int. (- 3, 0) and (1, 0)
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

y-int.: x = 0:

y = 2(0)² +4(0) - 6
y = - 6

y-int. (0, - 6)
¯¯¯¯¯¯¯¯¯¯¯

y = 2x^2 + 4x – 6

for y–intercept, it is x = 0 ;
so y = -6, i.e., (0, -6)

for x–intercept, let y=0,

2x^2 + 4x – 6 = 0

divided by 2 to all terms,

x^2 + 2x – 3 = 0

(x + 3)(x - 1) = 0

x = 1 or -3 ; i.e., (1, 0) and (-3, 0)