A radioactive substance decays continuously according to the formula N=Ce^kt, where N is the final amount, C is the initial amount, k is a constant, and t is the time in years. If 50 grams of substance decays to 20 grams in 10 years, determine the value of k.
I've been stuck on this problem for a while. Please show me in a multi-step format how to get the answer of -0.0916! Thank you :)
I've been stuck on this problem for a while. Please show me in a multi-step format how to get the answer of -0.0916! Thank you :)
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20 = (50)e^(10k)
2/5 = e^(10k)
ln(2/5) = lne^(10k)
ln(2/5) = 10k
[ln(2/5)] / 10 = k
k = -0.0916
:)
2/5 = e^(10k)
ln(2/5) = lne^(10k)
ln(2/5) = 10k
[ln(2/5)] / 10 = k
k = -0.0916
:)