(-2,2) (5,-5) find y=mx+b
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m = 2 + 5/ -2 -5 = -1
y - 2 = - ( x + 2)
--> y = -x
y - 2 = - ( x + 2)
--> y = -x
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Let me guess the teacher is Mrs. Finch
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the equation for linear type fraction is: Y-y1=m(X-x1)
M would be (y1-y2)/(x1-x2) so in this case we have M=(2-(-5))/(-2-5)=-1
so-----------------------> Y-2=-1(X-(-2))---------------->Y=-X+0---…
M would be (y1-y2)/(x1-x2) so in this case we have M=(2-(-5))/(-2-5)=-1
so-----------------------> Y-2=-1(X-(-2))---------------->Y=-X+0---…
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Use the form (y-y)=m(x-x)
so (-5-2)= m(5--2)
work it out and m= -1
so, y=-1x or in other words, y= -x
so (-5-2)= m(5--2)
work it out and m= -1
so, y=-1x or in other words, y= -x