Chemistry Queston. Please Help!

What volume of each of the following acids will react completely with 50.57 mL of 0.147 M NaOH?

(a) 0.170 M H2SO3 (two acidic hydrogens)

(b) 0.212 M H3PO4 (three acidic hydrogens)

(c) 0.255 M HC2H3O2 (one acidic hydrogen)

(d) 0.327 M H2SO4 (two acidic hydrogens)


answers are in mL (no need to convert mL to L)

I dont understand what the acidic hydrogens mean... can someone please explain how to solve??

What volume of each of the following acids will react completely with 50.57 mL of 0.147 M NaOH?

To completely react, the number of moles of OH-1 ions must equal the number of moles of H3O+1 ion.

Number of moles of H+ or OH- = Number of ions in formula * Molarity * Volume in liters

1st determine the number of moles of OH-1 ions in 50.57 mL of 0.147 M NaOH!
NaOH contains 1 OH-1 ion
Moles of OH-1 ions = 0.147 * 0.05057 = 0.00743379
So, you need 0.00743379 moles of H3O+1 ions.

Acidic hydrogens means the number of hydrogens that will react with water to produce hydronium ions.
0.0074337 = Number of ions in formula * Molarity * Volume in liters

Acid + water → H3O+1 ion + negative ion of acid.
H2SO3 + 2 H2O → 2 H3O+1 + SO3 -2
0.00743379 = 2 * 0.170 * Volume in liters, V = 0.02186 L


H3PO4 + 3 H2O → 3 H3O+1 + PO4 -3
0.00743379 = 3 * 0.212 * Volume in liters

HC2H3O2 + H2O → H3O+1 + C2H3O2 -1
0.00743379 = 1 * 0.255 * Volume in liters

H2SO4 + 2 H2O → 2 H3O+1 + SO4 -2
0.00743379 = 2 * 0.327* Volume in liters

OR
Volume of acid * Normality of acid = Volume of base * Normality of base

You convert molarity to normality.
Normality of acid = number of acidic hydrogens * molarity of acid

Volume of acid * (number of acidic hydrogens) * (molarity of acid)
= Volume of base * Normality of base
Normality of base = 0.147
a) V * 2 * 0.170 = 50.57 * 0.147, V = 21.86 ml
b) V * 3 * 0.212 = 50.57 * 0.147
c) V * 1 * 0.255 = 50.57 * 0.147
d) V * 2 * 0.327 = 50.57 * 0.147

you should do it yourself