Find the foci and asymptotes of the hyperbola ((x-1)^2/25)-((y+1)^2/16)=1
Please help out a bit,thank you
Please help out a bit,thank you
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foci
(1+sqrt41 , -1) , (1-sqrt41, -1)
asymptotes
y+1 = +/- (4/5)(x-1)
(1+sqrt41 , -1) , (1-sqrt41, -1)
asymptotes
y+1 = +/- (4/5)(x-1)
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Here a^2 = 25 and b^2 = 16
So 16 = 25((e^2 -1) or e^2 = 41/25 means e = (sqrt41)/5 So (sqrt41,0) and (-sqrt41, 0) are the foci and directrices are x = + or - 25/sqrt41
So 16 = 25((e^2 -1) or e^2 = 41/25 means e = (sqrt41)/5 So (sqrt41,0) and (-sqrt41, 0) are the foci and directrices are x = + or - 25/sqrt41