Let f(x,y)=(x^2)sin(xy). What is the gradient of f(x.y) at (1,pi)
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Let f(x,y)=(x^2)sin(xy). What is the gradient of f(x.y) at (1,pi)

[From: ] [author: ] [Date: 11-12-05] [Hit: ]
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Thanks ~

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The gradient is the vector of first partial derivatives.

∇f = <2x sin(xy) + x^2 y cos(xy), x^3 cos(xy)>.
==> ∇f(1, π) = <-π, -1>.

I hope this helps!
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