I need to prove the following.
4tanx = [4tanx - 4tan^3(x)] / [1 - 6tan^2(x) + tan^4(x)]
I know that I can do tan2x = [2tanx] / [1-tan^2(x)], but that's about all.
Please show me how to do this!!!
4tanx = [4tanx - 4tan^3(x)] / [1 - 6tan^2(x) + tan^4(x)]
I know that I can do tan2x = [2tanx] / [1-tan^2(x)], but that's about all.
Please show me how to do this!!!
-
4tanx = [4tanx - 4tan^3(x)] / [1 - 6tan^2(x) + tan^4(x)]
This is not an identity, so you shouldn't be able to prove it.
Here's how you can see that it is not true:
suppose x is 45 degrees. Then tan x = 1
left hand side = 4 But the numerator of the right hand side is (4-4)=0
Maybe you made a mistake typing the problem?
As written, the problem only involves tan(x), no multiple angles are involved.
This is not an identity, so you shouldn't be able to prove it.
Here's how you can see that it is not true:
suppose x is 45 degrees. Then tan x = 1
left hand side = 4 But the numerator of the right hand side is (4-4)=0
Maybe you made a mistake typing the problem?
As written, the problem only involves tan(x), no multiple angles are involved.