When iron metal reacts with oxygen, the reaction can form Fe2O3. Write a balanced chemical equation for this reaction, and find the number of moles of oxygen that are needed to form 6 mol of Fe2O3. Show your work.
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4 Fe + 3 O2 --> 2 Fe2O3 This basically says that 4 moles of iron plus 3 moles of oxygen yields 2 moles of iron oxide. To get 6 moles you need to multiply by 3 so you need 9 moles of oxygen.
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4 Fe (s) + 3 O2 (g) -----> 2 Fe2O3
3 moles of oxygen form 2 moles of iron (III) oxide.
If you set up a ratio, you have
(3 mol oxygen) / (2 mol iron (III) oxide) = (x mol oxygen) / (6 mol iron (III) oxide)
x = 9 moles of oxygen
3 moles of oxygen form 2 moles of iron (III) oxide.
If you set up a ratio, you have
(3 mol oxygen) / (2 mol iron (III) oxide) = (x mol oxygen) / (6 mol iron (III) oxide)
x = 9 moles of oxygen