What is the velocity of an object when it is h ft above the ground on the way up

Answer the question given the equation for height s(t) = 128t - 16t^2 where h = 208 ft

Hello

this is an equation for a vertical trajectory with initial velocity v0 = 128 ft/s according to
s = v0*t - 1/2*gt^2

And if you know v0, you can use
v^2 = v0^2 - 2gs with s = 208 ft
v^2 = 128^2 - 2*32*208
v^2 = 3072
v = 55.425 ft/s <-- ans.

Regards