they all have a common factor of 2 so you divide them by that, but why dont you put it out front? why is the answer (x+5)=0? shouldn't it be 2(x+5)=0?
-
2x^2 + 20x +50
2(x^2 + 10x +25)
2(x+5)(x+5)
Now if equation =0
multiplication resulting in a 0 means that one of the factors MUST be 0. 2 cannot =0 (thats why its ignored) so x+5 = 0
2(x^2 + 10x +25)
2(x+5)(x+5)
Now if equation =0
multiplication resulting in a 0 means that one of the factors MUST be 0. 2 cannot =0 (thats why its ignored) so x+5 = 0
-
If you are ONLY factoring it is 2(x + 5)^2
2(x^2 + 10x + 25)
2(x + 5)^2
IF you are solving....
2(x^2 + 10x + 25) = 0
2(x + 5)^2 = 0..............divide by 2
(x + 5)^2 = 0...............take square root of both sides
x + 5 = 0
x = - 5..........ANSWERS
2(x^2 + 10x + 25)
2(x^2 + 10x + 25)
2(x + 5)^2
IF you are solving....
2(x^2 + 10x + 25) = 0
2(x + 5)^2 = 0..............divide by 2
(x + 5)^2 = 0...............take square root of both sides
x + 5 = 0
x = - 5..........ANSWERS
2(x^2 + 10x + 25)
-
(2x+10)(x+5)=0
X= -5
You can divide the whole problem by two if u want, but just redistribute the two back to the first group of numbers in parenthesis when solving for x values
X= -5
You can divide the whole problem by two if u want, but just redistribute the two back to the first group of numbers in parenthesis when solving for x values
-
2(x^2+10x+25) 2(x+5)^2 x=-5 twice