49x^2 = 28x - 4
Please help me :(!!!
Please help me :(!!!
-
49x^2 = 28x - 4
Please help me :(!!!
quadratic equation...set equal to zero...
49x^2 - 28x + 4 = 0
perfect square trinomial...
(7x - 2)^2 = 0
x = 2/7 (double root)
check
(a - b)^2 = a^2 - 2ab + b^2
qed
Please help me :(!!!
quadratic equation...set equal to zero...
49x^2 - 28x + 4 = 0
perfect square trinomial...
(7x - 2)^2 = 0
x = 2/7 (double root)
check
(a - b)^2 = a^2 - 2ab + b^2
qed
-
49x^2 - 28x + 4 = 0
(7x - 2)^2 = 0
x = 2/7
(7x - 2)^2 = 0
x = 2/7