(π=pie)
Make the variables in the brackets the subject
A) A = πR².........(R)
B) (A + B)² = C.......(B)
Transpose the following equations
A) V² = U² +2AS.........(A)
B) A = 2π² + 2πrh...........(H)
Would be good if you could give it step by step and not just the answer
thanks :D
Make the variables in the brackets the subject
A) A = πR².........(R)
B) (A + B)² = C.......(B)
Transpose the following equations
A) V² = U² +2AS.........(A)
B) A = 2π² + 2πrh...........(H)
Would be good if you could give it step by step and not just the answer
thanks :D
-
A1)
A = πR^2
R^2 = A/π
R = SQRT(A/π)
B1)
(A+B)^2 = C
A^2 + 2AB + B^2 = C^2
B^2 + 2AB + (A^2 - C^2) = 0
using the quadratic formula with a = 1, b = 2A, and c = (A^2 - C^2) we get:
B = -A +/- C
A2)
V^2 = U^2 + 2AS
2AS = V^2 - U^2
A = (V^2 - U^2) / 2S
B2)
A = 2π^2 + 2πrH
2πrH = A - 2π^2
H = (A - 2π^2) / 2πr
Best of luck!
A = πR^2
R^2 = A/π
R = SQRT(A/π)
B1)
(A+B)^2 = C
A^2 + 2AB + B^2 = C^2
B^2 + 2AB + (A^2 - C^2) = 0
using the quadratic formula with a = 1, b = 2A, and c = (A^2 - C^2) we get:
B = -A +/- C
A2)
V^2 = U^2 + 2AS
2AS = V^2 - U^2
A = (V^2 - U^2) / 2S
B2)
A = 2π^2 + 2πrH
2πrH = A - 2π^2
H = (A - 2π^2) / 2πr
Best of luck!