Calculus question, pls help me solve

Differentiate by natural log.
y=ln2x
pls send me ur answers with step by step detail.
Thanks

Use the formula (lnU)' = U'/U which includes the chain rule

U = 2x, U' = 2; so the answer is y' = (ln2x)' = 2/(2x) = 1/x

Note: This is the same marginal rate of change as y = lnx

Derivative of ln(x) is 1/x. Then use the chain rule and multiply by the derivative of 2x, which is 2.
So the derivative is 2/x.